A 10 kg box slides down a ramp inclined 30 degrees to the horizontal. How great is the normal force by the ramp on the box?

normal-force
degrees-horizontal

#1

a 10 kg box slides down a ramp inclined 30 degrees to the horizontal. How great is the normal force by the ramp on the box?

Answer:

g * 10 * cos(30º)

Formula for this question:
N = mgcos(theta)

N = 10 kg9.8 m/s^2cos(30)

N= 17.32 N