A 10.0 V battery is connected across two resistors in series. If the resistors have resistances of 840.0 Ω and 590.0 Ω

resistors-series

#1

A 10.0 V battery is connected across two resistors in series. If the resistors have resistances of 840.0 Ω and 590.0 Ω , what is the voltage drop across the 590.0 Ω resistor?
A) 4.1 V
B) 5.9 V
C) 14 V
D) 7.0 V

Answer:

10.0 v * [590.0 / (840.0 + 590.0)]