4 NH3 (g) + 5 02 (g) forms 4 NO (g) + 6 H20 (g). How many liters of NH3 (g) at 850 degrees celcius and 5.00 atm are required to react

degrees-celcius

#1

4 NH3 (g) + 5 02 (g) forms 4 NO (g) + 6 H20 (g). How many liters of NH3 (g) at 850 degrees celcius and 5.00 atm are required to react with 1 mol of 02 (g) in this reaction?

Answer:

First find moles of nh3 using mole ratio:
(1mole 02)((4mole nh3)/(5mole 02))=0.8 moles of nh3.
Convert celcius to kelvin:
850+273.15=1123.15k
Then use pv=nrt to solve for v:
(5)(v)=(.8)(.0821)(1123.15)
v=((.8)(.0821)(1123.15)/(5))
v=14.754 L