Given conditions

$V_{ 1 }$ = 35 mL

$p_{ 1 }$ = 758 mm

$T_{ 1 }$ = 6 + 273 = 279 K

Final conditions

$V_{ 2 }$ = ?mL

$p_{ 2}$ = 760 mm

$T_{ 2 }$ = 0+273 = 273 K

By applying gas equation, we have

760 x $V_{ 2 }$/273 = 758 x 35 /279

$V_{ 2 }$ = 758 x 35 x 273/279 x 760=34.16 mL

Volume of chloride gas = 34.16 mL