**30 mL of pure water at 280. K is mixed with 50.0 mL of pure water at 3230. K. What is the**

Answer:

305k

Calculation

(30g)CH2O(TF-280)=(50g)Ch2O(320-TF)

30TF-8400=16000-50 TF

80TF=16000+8400

ANSWER =24400/80

=305K

of the mixture in kelvin?**

**Answer:**

answer 305k

Calculation

(30g)CH2O(TF-280)=(50g)Ch2O(320-TF)

30TF-8400=16000-50 TF

80TF=16000+8400

ANSWER =24400/80

=305K