30 mL of pure water at 280. K is mixed with 50.0 mL of pure water at 3230. K. What is the final temperature of the mixture in kelvin?

pure-water

#1

30 mL of pure water at 280. K is mixed with 50.0 mL of pure water at 3230. K. What is the

Answer:

305k
Calculation
(30g)CH2O(TF-280)=(50g)Ch2O(320-TF)
30TF-8400=16000-50 TF
80TF=16000+8400
ANSWER =24400/80
=305K
of the mixture in kelvin?**

Answer:

image

answer 305k
Calculation
(30g)CH2O(TF-280)=(50g)Ch2O(320-TF)
30TF-8400=16000-50 TF
80TF=16000+8400
ANSWER =24400/80
=305K