**2D motion problem**

**Answer:**

Asuming the ball hits the ledge at it’s highest point, we can solve this problem. If we do not make this assumption, there is not enough information to solve the problem.

We can break the initial velocity into 2 components, vertical and horizontal, each at sqrt(10^2/2)=7.07m/s.

Since the vertical velocity is 7.07m/s, using t=(vf + vi)/(2d)=(7.07m/s)/(2*2m)=1.7678sec

The horizontal velocity is not subject to acceleration (vertical velocity is subject to gravity), the velocity is constant. Therefore, the horizontal velocity is 7.07m/s and the ball traels for 1.767 sec so the product is 12.498m.