**212 people surveyed, 72% favored home team. Find margin of error and give interval that is likely to contain exact percent. HELP?**

**Answer:**

using the formula for margin of error, ±(1/√n)

±(1/√212)

±0.06868 this is the margin of error

to find the interval, you subtract and add this number from your %

72- 0.06868= 71.9313

72+0.06868=72.0687

the interval is 71.9313<M<72.0687