212 people surveyed, 72% favored home team. Find margin of error and give interval that is likely to contain exact percent. HELP?
using the formula for margin of error, ±(1/√n)
±0.06868 this is the margin of error
to find the interval, you subtract and add this number from your %
72- 0.06868= 71.9313
the interval is 71.9313<M<72.0687