1/(Tanx+Cotx) =sinxcosx

1tanxcotx-sinxcosx

#1

1/(Tanx+Cotx) =sinxcosx

Answer:

tanx + cot x = sinx/cosx + cosx/sinx
=sin^2 (x) + cos^2 (x) /sinxcosx
now sin^2 (x) + cos^2 (x) = 1

so tanx+ cotx = 1/sinxcosx
or 1/tanx+cotx = sinxcosx